I have the next limit: limn→∞(n√(n!−1n!+1)(n+1)!)
I had done some steps and simplified it to:
limn→∞(1−2n!+1)(n+1)(n−1)!=limn→∞(1−1(n(n−1)!+1)⋅0.5)(n+1)(n−1)!
And my final result is:
limn→∞(1e)3n+2+1(n−1)!2
My question is what happens to 1(∞−1)!? Is it 0?
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