I think you might have to use Squeeze Theorem here? I've confused myself.
$$\lim_{x \to 0+}\frac{1}{x}-\frac{1}{\arctan(x)}$$
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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