What have I done wrong?
I have to evaluate the following integral:
∞∫02π∫0ϕ(r2)δ′(r2−a)δ(θ−(n+12)π2)rdθdr
My (wrong) working:
⟹4∞∫0ϕ(x)δ′(x−a)12dx by letting x=r2
⟹−2ϕ′(a)
I should be getting the integral equalling ϕ(a)−ϕ′(a).
Thank you.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
No comments:
Post a Comment