Friday, 21 March 2014

special functions - Integration error spotting

What have I done wrong? 




I have to evaluate the following integral:



02π0ϕ(r2)δ(r2a)δ(θ(n+12)π2)rdθdr



My (wrong) working:



40ϕ(x)δ(xa)12dx by letting x=r2



2ϕ(a)




I should be getting the integral equalling ϕ(a)ϕ(a).



Thank you.

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