I am interested in the properties of symmetric hollow matrices (diagonal full of zeros) for which all off-diagonal terms are strictly positive. An example for n=3 would be
[0A21A31A210A32A31A320]
where A21, A31 and A32 are all strictly positive. Let's call the set of these matrices B.
Now consider the subspace S:∑ixi=0. I want to show that matrices in B are negative definite on S. I.e. for all x∈S and for a matrix A∈B we have x′Ax≤−d‖x‖ for some d>0. This seems to be the case for n=2 and n=3 but I would like a general proof. If the result does not hold, could we show that matrices in B are negative semi definite on S instead?
Answer
Not true. For example, with n=3 take x=(11−2) with A21 very large. A21>2A31+2A32 will do.
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