Friday, 16 September 2016

linear algebra - Are hollow positive symmetric matrices negative definite on subspace sumixi=0?



I am interested in the properties of symmetric hollow matrices (diagonal full of zeros) for which all off-diagonal terms are strictly positive. An example for n=3 would be




[0A21A31A210A32A31A320]
where A21, A31 and A32 are all strictly positive. Let's call the set of these matrices B.




Now consider the subspace S:ixi=0. I want to show that matrices in B are negative definite on S. I.e. for all xS and for a matrix AB we have xAxdx for some d>0. This seems to be the case for n=2 and n=3 but I would like a general proof. If the result does not hold, could we show that matrices in B are negative semi definite on S instead?


Answer



Not true. For example, with n=3 take x=(112) with A21 very large. A21>2A31+2A32 will do.


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