If I want to solve an equation like $x' = -2t(x+1)$, I will write $$\dfrac{dx}{dt} = x'\;\;\implies\;\;\dfrac{dx}{dt} = -2t(x+1)$$ and then I can solve it for $x$.
But why is it possible to write $\dfrac{dx}{dt}$ instead of $x'$?
Answer
...why is it possible to write $\dfrac{dx}{dt}$ instead of $x'$?
$$x' = -2t(x+1)\iff \frac{dx}{dt} = -2t(x+1)$$
I.e., $\;x'\;$ is "shorthand" for $\;\dfrac{dx}{dt}$.
What's nice about $\;\dfrac{dx}{dt}\;$ is that it specifies the derivative of $\;x\;$ with respect to $\;t$.
But the same is taken as given when you see $\;x' = -2t(x+1),\;$ which is more brief than using $\;\dfrac{dx}{dt} = -2t(x+1)$.
If you also have $y' = at(y + b)$ where $a, b$ are given, you could write $\;\dfrac{dy}{dt} = at(y + b)$. If you know $\;\dfrac{dy}{dt}\;$ and $\;\dfrac{dx}{dt},\;$ you can solve for $dy/dx$:
$$
\begin{align*} \dfrac{dy}{dx}\dfrac{dx}{dt} &= \dfrac{dy}{dt} \\ \\
\text{So}\;\;\;\dfrac{dy}{dx} &= \dfrac{dy/dt}{dx/dt}\end{align*}$$
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