Monday, 26 September 2016

sequences and series - Polynomial for product over a set


Conjecture:
If A is a nonempty, finite set with size |A|=n, and
PA(x)=aA(xa),
then PA(x) can be expanded as

PA(x)=nk=0(1)nkxkUA|U|=nkuUu.




I have conjectured this based on algebraic evidence. That is, I expanded out the cases n=1,...,4 both manually and through (1), and in each case the conjecture held. The problem is, I'm having difficulty proving this result. I'm fairly certain that a proof would involve induction, but I'm not very good at that, and have so far failed.



I was initially interested in this formula because I recognized that (1) would imply that
k0,nUSn|U|=kuUu=0
for
Sn={exp2πikn:k=0,1,...,n1}.
It may seem un-intuitive at first, but (2) is true because

PSn(x)=xn1,
(as Sn is the set of roots of xn1) so each term of the expansion must vanish except for the cases k=0,n.



After seeing this, I was naturally curious about a proof of (1). Could I have some help or hints? Thanks.

No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...