We want to find the [Q(√2+√3)(√5):Q(√2+√3)].
My first thought is to find the minimal polynomial of √5 over Q(√2+√3). And from this, to say that [Q(√2+√3)(√5):Q(√2+√3)]=degm√5,Q(√2+√3)(x).
We take the polynomial m(x)=x2−5∈Q(√2+√3)[x]. This is a monic polynomial which has √5∈R as a root. We have to show that this is irreducible over Q(√2+√3), in order to say that m(x)=m√5,Q(√2+√3)(x). The roots of m(x) are ±√5∈R. So,
m(x) is irreducible over Q(√2+√3)⟺±√5∉Q(√2+√3)=Q(√2,√3)
because degm(x)=2.
And this is the point I stack. I tried with the use of the basis of the Q-vector space Q(√2+√3):
A:={1,√2,√3,√6}
in order to claim that ∄a,b,c,d∈Q:√5=a+b√2+c√3+d√6 but this doesn't help.
Any ideas please?
Thank you in advance.
No comments:
Post a Comment