Limit of $lim_{xto0} left(frac{1}{x}-cot xright)$ without L'Hopital's rule

Is it possible to evaluate

$$\lim_{x\to 0} \left(\frac{1}{x}-\cot x\right)$$ without L'Hopital's rule? The most straightforward way is to use $\sin{x}$ and $\cos{x}$ and apply the rule, but I stuck when I arrived to this part (since I don't want to use the rule as it is pretty much cheating):

$$\lim_{x\to0} \left(\frac{\sin{x}-x\cos{x}}{x\sin{x}}\right)$$

It seems like there's something to do with the identity

$$\lim_{x\to0} \frac{\sin{x}}{x}=1$$
but I can't seem to get the result of $0.$