A student recently used the series ∞∑k=1sin2kk as an example of a divergent series whose terms tend to 0. However, I'm having trouble convincing myself that this series does in fact converge. Anyone have any ideas?
Answer
The series diverges. Notice
sin2(k)+sin2(k+1)=12(1−cos(2k))+12(1−cos(2k+2))=1−cos(1)cos(2k+1)≥1−cos(1)
We have 2N∑k=1sin2(k)k=N∑k=1(sin2(2k−1)2k−1+sin2(2k)2k)≥1−cos(1)2N∑k=11k
which diverges to ∞ as N→∞.
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