Looking for some help and explanation on some questions that require FTC.
I will be using the following versions of FTC. I have made an attempt but they do not correspond to the solutions I was given out so am looking for feedback on why my method is incorrect.
FTC 1
Let f be regulated on the interval [a,b] and f is continuous on at c∈(a,b). Then F(x)=∫xaf is differentiable on (a,b) with F′(c)=f(c)
FTC 2
Let f:[a,b]→R be continuous and let g:[a,b]→R be differentiable with g′(x)=f(x)∀x∈[a,b]. Then ∫baf=g(b)−g(a)
Questions
1) Let I=∫ba1logxdx
Find: dIda,dIdb
So my method is to let F be such that F′=1logx, and then using FTC2, I get I=F(b)−F(a). After differentiation I get 1loga,−1logb respectively.
Now the solutions suggest that I split the integral up into ∫b2,∫2a=∫b2−∫a2, and then differentiate here. Am I missing something about the conditions? Do I need to rearrange each equation into the indefinite integral?
2) Same as above except now I=∫b(x)a(x)1logxdx I need to find I′(x) a(x) and b(x) are functions with values in [2,∞)
In the form of b(x), a(x) I can't seem to rearrange it into the indefinite integral form. From the solutions they still seem to recommend that I write
I(x)=J(a(x))−J(b(x)) where J(a)=∫a21logtdt and then differentiating with the chain rule. I don't understand why this is necessary, as to me, an unrigorous solution that uses the same idea ddx(F(b(x))−F(a(x)) does the same thing, so why do we need to split the integral like this?
3) Can someone give me an example of how they would split ∫1+x2x2f(t)dt,x∈R
4) Where do I need to comment about differentiability / continuity? Do I need to prove that the functions I here are continuous before I use the theorem?
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