So if so a≡b(modn), which should be read as "a is congruent to b modulo n" which from what I understand is something among the lines of "a is the remainder when b is divided by n".
Now, given 51≡41(mod5) means the remainder of 41 divided by 5 is 1, so this is a? I am confused as a looks to be 51?
Answer
41(mod5)≡1(mod5) (This is 415, with a remainder of 1.)
51(mod5)≡1(mod5) (This is 515, also with a remainder of 1.)
Therefore: 41≡51(mod5).
a≡1(mod5)
b≡1(mod5)
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