Sunday 17 March 2013

real analysis - Does there exist a convex function which is not strictly differentiable almost everywhere?

It is known that:



(i) There exists a locally Lipschitz function on an Euclidean finite-dimensional space which is almost everywhere (almost everywhere means "except a set with Lebesgues measure zero") Frechet differentiable but is not almost everywhere strictly differentiable.



(ii) Any convex function on an Euclidean finite-dimensional space is strictly differentiable except a set of the first category.



(iii) There exists a set of the first category on $\mathbb R$, the complement of which has Lebesgues measure zero.




I have a question: Does there exist a convex function on an Euclidean finite-dimensional space which is not almost everywhere strictly differentiable?



Note that for a convex function, strictly differentiable at a point means that its subdifferential of convex analysis reduces to a singleton.

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...