limy→0ycos(π2(1+y))
Can anybody help me? I can use basic properties of limits, and some of those basic known limits. I know it would be easier with derivatives, but I was just wondering if it's possible without L-Hospital's rule, derivatives, Taylor series.
Thank you in advance!
My ideas for now:
changing cosine into sine.
Maybe that. I have no other clue.
Answer
Note that limy→0ycos(π2(1+y))=limy→0ycos(π2+πy2)=limy→0y−sin(πy2)=−2πlimy→0(πy2)sin(πy2)=−2π(1)=−2π
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