if an is monotonic increasing/decreasing show that sequence
An=a1+a2+...ann is also monotonic increasing/decreasing.
my attempt:
I intially thought of using induction since A2>A1 when a2>a1 so base case is available. but to prove An+1>An doesnt show up easy. Any other way?
Answer
Proving the generalized case is very similar to the base case, because you can write An+1=nn+1An+1n+1an+1, which looks very similar to A2=12A1+12a2
Basically, it amounts to stating why the relative contribution from an+1 is at least as large as the relative contribution from any of the previous elements $a_j, j
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