Sunday 26 January 2014

complex analysis - Convergence of Laurent Series.

Let $f(z)$ be analytic for $|z|>r$ and let it be bounded $|f(z)|\leq M, M>0$ wherever it is analytic. Show that the coefficients of the Laurent Series of $f(z)$ are $0$ for $j\geq 1$.




I have found two approaches to solve this. I'm not sure about this one:



The positive part of the Laurent Series:



$$\sum_{j=0}^\infty a_j(z-z_0)^j$$



converges when $|z-z_0|

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...