Sunday, 12 January 2014

real analysis - Convergent sequence and limlimitsntoinftyn(an+1an)=0




Let (an)n be a real, convergent, monotonic sequence. Prove that if the limit limnn(an+1an)

exists, then it equals 0.





I tried to apply the Stolz-Cesaro theorem reciprocal:
limnn(an+1an)=limnan1+12++1n1=0

but I can't apply it since for bn=1+12++1n1 we have limnbn+1bn=1. I also attempted the ϵ proof but my calculations didn't lead to anything useful.


Answer



Hint. You are on the right track. Note that an is convergent to a finite limit and the harmonic series at the denominator is divergent. Therefore
0=limnan1+12++1n1SC=limnan+1an1n=limnn(an+1an).


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