Let (an)n be a real, convergent, monotonic sequence. Prove that if the limit limn→∞n(an+1−an)
exists, then it equals 0.
I tried to apply the Stolz-Cesaro theorem reciprocal:
limn→∞n(an+1−an)=limn→∞an1+12+⋯+1n−1=0
but I can't apply it since for bn=1+12+⋯+1n−1 we have limn→∞bn+1bn=1. I also attempted the ϵ proof but my calculations didn't lead to anything useful.
Answer
Hint. You are on the right track. Note that an is convergent to a finite limit and the harmonic series at the denominator is divergent. Therefore
0=limn→∞an1+12+⋯+1n−1SC=limn→∞an+1−an1n=limn→∞n(an+1−an).
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