Once , I do a problem ∑14n=1cos(n2π14)
when angle modular by 28 we've got
2(cos(π14)−cos(2π14)+cos(3π14)+cos(4π14)−cos(5π14)−cos(6π14))+1
and then using identity cos(a)−cos(b) and cos(a)+cos(b)
leads to 2√2(cos(π28)−cos(3π28)+sin(5π28))+1
the final answer is √7 but I don't know how to compute (cos(π28)−cos(3π28)+sin(5π28)) by hands.
I appreciate for your helps.
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