f:[0,1]→R is a continuous function which satisfies
f(x)+f(1−x)+f(√x2+(1−x))=0 and f(12)=0.
Can someone give explicit examples of f, apart from the trivial solution, f(x)=0? And are there infinitely many solutions for f?
I can derive some properties like f(√32)=0 or f(0)=−2f(1), but I can't generate particular examples. Continuity seems important here, but I can't see how to use it, for if we take f(x)=0, for x∈(0,1), and f(1)=1, f(0)=−2 also works.
Answer
First, notice that √x2+1−x≥√3/2 for all x∈[0,1]. Let g:[1/2,√3/2]→R be an arbitrary continuous function such that g(1/2)=g(√3/2)=0. Then, define f:[0,1]→R as follows:
f(x)={0if x∈[0,1−√3/2],−g(1−x)if x∈(1−√3/2,1/2],g(x)if x∈(1/2,√3/2],0if x∈(√3/2,1].
For example:
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