What I have tried so far is this
The function $$\lim_{x\to\infty} \frac{x}{\sqrt[]{ x^2+1 }}$$
Seems to be in the Indeterminate Form of $$\frac{\infty}{\infty}$$
Yet the limit when solved using L' Hopital's rule is $$\lim_{x\to\infty} \frac{1}{(\frac{x}{\sqrt[]{x^2+1}})}$$
which equals $$\frac{1}{undefined}$$
but the limit equals 1 not undefined.
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