Wednesday, 7 September 2016

calculus - How to solve the limit without graphing limxtoinftyfracxsqrt[]x2+1

What I have tried so far is this



The function lim



Seems to be in the Indeterminate Form of \frac{\infty}{\infty}



Yet the limit when solved using L' Hopital's rule is \lim_{x\to\infty} \frac{1}{(\frac{x}{\sqrt[]{x^2+1}})}
which equals \frac{1}{undefined}




but the limit equals 1 not undefined.

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