How do I evaluate this without using Taylor expansion?
$$\lim_{x \to \infty}x^2\log\left(\frac {x+1}{x}\right)-x$$
Note: I used Taylor expansion at $z=0$ and I have got $\frac{-1}{2}$
Thank you for any help
How do I evaluate this without using Taylor expansion?
$$\lim_{x \to \infty}x^2\log\left(\frac {x+1}{x}\right)-x$$
Note: I used Taylor expansion at $z=0$ and I have got $\frac{-1}{2}$
Thank you for any help
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