How do I evaluate this without using Taylor expansion?
limx→∞x2log(x+1x)−x
Note: I used Taylor expansion at z=0 and I have got −12
Thank you for any help
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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