How can an image of [0,1] fill a square? It seems to me that it would have to be DISCONTINUOUS, so it wouldn't satisfy the definition of a curve.
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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