I am given the limit limx→0+lnx√x.
As far as I am concerned lnx→−∞ and √x→0 so I got [−∞0] . What should I do next? Should I transform it and then use de l'Hospital rule? [−∞0] is not indeterminate form so how should I deal with this?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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