Monday, 28 October 2019

real analysis - Verification of limnrightarrowinftysqrt[n]n3=1




I am interested in the limit




limnnn3




Can we simply conclude that:
limn(nn)3=13=1.



I have proven that nn1 earlier in this textbook. Also since the limit of a power is the power of the limit.


Answer



Yes, we can simply do that. Since the exponent 3 is a constant neutral number (meaning we may interpret it as a fixed number of multiplications) we can move the limit inside of it. So if you already know limnnn=1 then that's a full proof.


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