Saturday, 6 July 2013

sequences and series - How to evaluate this limit and its convergence? sumin=1nftyfrac1nsqrt[n]n



How to evaluate this limit
n=11nnn

and its convergence?



I tried ratio test, root test, Raabe's test. However, I'm not getting anywhere. Can you please help me? Thank you


Answer



For n sufficiently large, nn<2; so,
1nnn>12n for sufficiently large n.



Since the series n=112n diverges (it is essentially the harmonic series), it follows from the Comparison test that the series n=11nnn diverges.


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