How to evaluate this limit
∞∑n=11nn√n
and its convergence?
I tried ratio test, root test, Raabe's test. However, I'm not getting anywhere. Can you please help me? Thank you
Answer
For n sufficiently large, n√n<2; so,
1nn√n>12n for sufficiently large n.
Since the series ∞∑n=112n diverges (it is essentially the harmonic series), it follows from the Comparison test that the series ∞∑n=11nn√n diverges.
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