Monday, 22 July 2013

calculus - Evaluating intxsin1xdx

I was integrating xsin1xdx.


After applying integration by parts and some rearrangement I got stuck at 1x2dx.

Now I have two questions:





  1. Please, suggest any further approach from where I have stuck;


  2. Please, provide an alternative way to solve the original question.






Please help!!!

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