Prove that the sequence an=1⋅3⋅5⋯(2n−1)2⋅4⋅6⋯(2n)
is monotonically decreasing sequence. I tried an+1−an<0, but i was not able to do it.
Help will be appreciated.
Thanks!
Answer
Notice, we have an=1.3.5…(2n−1)2.4.6…(2n)
=[1.3.5…(2n−1)]⋅[2.4.6…(2n)][2.4.6…(2n)]⋅[(2.4.6…(2n)]
=1.2.3.4.5…(2n−1)(2n)[2.4.6…(2n)]2
=(2n)![2n(1.2.3…(n))]2
=(2n)![2n(n!)]2
an=(2n)!22n(n!)2
⟹an+1=(2n+2)!22n+2((n+1)!)2
⟹an+1=(2n+2)(2n+1)(2n)!4⋅22n((n+1)n!)2
=2(n+1)(2n+1)(2n)!4(n+1)2⋅22n(n!)2
an+1=(2n+1)(2n)!2(n+1)⋅22n(n!)2
Now, dividing (2) by (1), we get an+1an=(2n+1)(2n)!2(n+1)⋅22n(n!)2(2n)!22n(n!)2
=2n+12(n+1)
an+1an=2n+12n+2<1
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