Thursday, 22 May 2014

algebra precalculus - How to get the simplest form of this radical expression: 3sqrt[3]2a6sqrt[3]2a.




How to get the simplest form of this radical expression:
332a632a



Here is my work:
332a632a
Since the radicands are the same, we just add the coefficients.
332a32a
Since everything is under the same index it becomes:
3323a




Did I do this correctly, if not can anyone tell me what I should do?
Thanks :-).


Answer



Your middle step is incorrect, it should be 332a not 332a32a. It should be 332a632a=3×32a6×32a=(36)×32a=3×32a=332a. I don't think 3323a is any simpler than 332a, but that's just my opinion.


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