What a weird function.
I tried to find out: $$\lim_{x\to\infty } \frac{\ln x}{\sqrt{x}\,{\sin{x}}}$$
So, I can't use L'Hopital 'cause there's no actual limit in the denominator. It doesn't exist.
Then, I tried to use Heine's theorem and chose two sequences, but yet I got the same limit.
I believe it does not converge. How can I prove it?
Thanks
Answer
You can consider a sequence $x_n = \pi n - 2^{-n}$. On this sequence your function will become unbounded while this sequence goes to infinity. Hence the limit does not exist.
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