Dirac and Pauli are playing a game with an ordinary six-sided die. Dirac’s target numbers are
1, 2, 3, and Pauli’s target numbers are 4, 5, 6. They take turns in rolling the die, with Dirac going first. If the one whose turn it is rolls a target number which he has not previously rolled, he gets to roll again; if he rolls a target number which he has previously rolled, or a number which is not one of his target numbers, his turn ends. The first player to have rolled all three of his target numbers (not necessarily all in the one turn) wins. What is the probability that Dirac wins?
Tuesday, 13 May 2014
Difficult probability with a Die
Subscribe to:
Post Comments (Atom)
real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$
How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
-
I'm just learning how to test series for convergence and have encountered this series from the Demidovich's book and I can't rea...
-
Ok, according to some notes I have, the following is true for a random variable $X$ that can only take on positive values, i.e $P(X $\int_0^...
-
Make a bijection that shows $|\mathbb C| = |\mathbb R| $ First I thought of dividing the complex numbers in the real parts and the c...
No comments:
Post a Comment