So I'm trying to evaluate the triple integral $$\displaystyle \iiint \limits_{R} \displaystyle \frac{1}{((x-a)^2+y^2+z^2)^{1/2}} \mathrm dV$$ for $a>1$ over the solid sphere $0 \leq x^2 + y^2 + z^2 \leq 1$.
Apparently, there's an interpretation that I should be able to draw from this to. Not too sure what it is.
So the first thing that came to mind when I saw the integral was to apply spherical coordinates, but this doesn't make the denominator of the integrand any less messy.
Using spherical coordinates, the integrand becomes
$$\displaystyle \iiint \limits_{R} \displaystyle\frac{1}{(\rho^2-2a\rho\sin\phi\cos\theta+a^2)^{1/2} } \rho^2\sin\phi \space\mathrm d\rho\mathrm d\phi\mathrm d\theta$$ (I haven't bothered to add the bounds yet), which doesn't look that much more friendly.
Any support for this question would be appreciated.
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