If I want to solve an equation like x′=−2t(x+1), I will write dxdt=x′⟹dxdt=−2t(x+1)
and then I can solve it for x.
But why is it possible to write dxdt instead of x′?
Answer
...why is it possible to write dxdt instead of x′?
x′=−2t(x+1)⟺dxdt=−2t(x+1)
I.e., x′ is "shorthand" for dxdt.
What's nice about dxdt is that it specifies the derivative of x with respect to t.
But the same is taken as given when you see x′=−2t(x+1), which is more brief than using dxdt=−2t(x+1).
If you also have y′=at(y+b) where a,b are given, you could write dydt=at(y+b). If you know dydt and dxdt, you can solve for dy/dx:
dydxdxdt=dydtSodydx=dy/dtdx/dt
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