Saturday, 28 February 2015

logarithms - Prove that 5/2<e<3?




Prove that 52<e<3




By the definition of log and exp,
1=log(e)=e11tdt



where e=exp(1).



So given that e is unknown, how could I prove this problem? I think I'm missing some important facts that could somehow help me rewrite e in some form of 3 and 5/2. Any idea would be greatly appreciated.


Answer



e=limn(1+1n)n



the rth term $t_r=\frac{n(n-1)(n-2)\cdots(n-r+1)}{r!n^r}=\frac1{r!}\prod_{0\le s

So, limntr=1r!




So, e=1+11!+12!+13!+



But 1+11!+12!+13!+>1+1+0.5=2.5



Again,



3!=1.2.3>1.2.2=22



4!=1.2.3.4>1.2.2.2=23




So,



e=1+11!+12!+13!+
<1+1+12+122+123+
=1+(1+12+122+123+)=1+1112=3
as the terms inside parenthesis forms an infinite geometric series with the common ratio =12, the 1st term being 1


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...