Prove that 52<e<3
By the definition of log and exp,
1=log(e)=∫e11tdt
where e=exp(1).
So given that e is unknown, how could I prove this problem? I think I'm missing some important facts that could somehow help me rewrite e in some form of 3 and 5/2. Any idea would be greatly appreciated.
Answer
e=limn→∞(1+1n)n
the rth term $t_r=\frac{n(n-1)(n-2)\cdots(n-r+1)}{r!n^r}=\frac1{r!}\prod_{0\le s
So, limn→∞tr=1r!
So, e=1+11!+12!+13!+⋯
But 1+11!+12!+13!+⋯>1+1+0.5=2.5
Again,
3!=1.2.3>1.2.2=22
4!=1.2.3.4>1.2.2.2=23
So,
e=1+11!+12!+13!+⋯
<1+1+12+122+123+⋯
=1+(1+12+122+123+⋯)=1+11−12=3
as the terms inside parenthesis forms an infinite geometric series with the common ratio =12, the 1st term being 1
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