Two players P and Q take turns, in which they each roll two fair and independent dice. P rolls the dice first.
The first player who gets a sum of seven wins the game. What is the probability that player
P wins the game?
Answer
I'm going to assume P goes first. The question should have said so, unless something else was intended, in which case it's unclear.
Let (lower-case) p be the probability that P ultimately wins. Then
p=Pr
So solve the following:
p =\frac 1 6 + \frac 5 6 (1-p).
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