Wednesday, 29 July 2015

calculus - How to show that intpi/20intpi/20left(fracsinphisinthetaright)1/2,dtheta,dphi=pi?

π/20π/20(sinϕsinθ)1/2dθdϕ=π
Indeed, I tried to solve this integral by complexifying (using Euler's formula) the sinθ and sinϕ.But it didn't work because I faced the exponent which would make things difficult to tackle such integral.



I would appreciate any suggestions for solving this integral.

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