An infinite geometric series has the first term a and sum to infinity b, where b ≠0. Prove that a lies between 0 and 2b.
→Since the series converges, r has to be between 0 and 1 (using the geometric series formula, i.e a(1−rn)1−r):The sum=b=a1−r, where r is the common ratio.→b−br=a
Ok. Now what? I'm stuck.
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