abstract algebra - How to show that if p is prime and m,n are natural numbers then $p^m -1 | p^n -1$

Saturday, 19 December 2015

abstract algebra - How to show that if p is prime and m,n are natural numbers then $p^m -1 | p^n -1$

How to show that if $p$ is prime and $m,n$ are natural numbers such that $m|n$

then

$p^m -1 | p^n -1$

I'm really stucked with this problem. Please help? Thanks!

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