I'm trying to solve:
∞∫0x1/31+x2dx
I have tried contour integration with C+R and the real line like this:
∫Tz1/31+z2dz=∞∫−∞z1/31+z2dz+∫C+Rz1/31+z2dz
Where the last integral tends to 0 as R⟶∞
Res(f(z);i)=i1/32i
and
∞∫−∞z1/31+z2dz=∞∫0z1/31+z2dz+0∫−∞z1/31+z2dz
If i manipulate the last term by changing the limits and substitute u=−t i get:
0∫−∞z1/31+z2dz=−−∞∫0z1/31+z2dz
If i now substitue u=−z,u′=−1
0∫−∞z1/31+z2dz=∞∫0(−u)1/31+u2dz=(−1)1/3∞∫0u1/31+u2dz
∞∫−∞z1/31+z2dz=(1+eiπ3)∞∫0z1/31+z2dz
So i end up with:
2i⋅π⋅ei⋅π/62i⋅(1+eiπ3)=π⋅ei⋅π/6(1+eiπ3)=∞∫0z1/31+z2dz which is wrong answer
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