Thursday, 24 December 2015

complex analysis - Solving the improper integral inti0nftyfracx1/31+x2mathrmdx

I'm trying to solve:



0x1/31+x2dx



I have tried contour integration with C+R and the real line like this:



Tz1/31+z2dz=z1/31+z2dz+C+Rz1/31+z2dz



Where the last integral tends to 0 as R




Res(f(z);i)=i1/32i



and



z1/31+z2dz=0z1/31+z2dz+0z1/31+z2dz



If i manipulate the last term by changing the limits and substitute u=t i get:



0z1/31+z2dz=0z1/31+z2dz




If i now substitue u=z,u=1



0z1/31+z2dz=0(u)1/31+u2dz=(1)1/30u1/31+u2dz



z1/31+z2dz=(1+eiπ3)0z1/31+z2dz



So i end up with:



2iπeiπ/62i(1+eiπ3)=πeiπ/6(1+eiπ3)=0z1/31+z2dz which is wrong answer

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