Thursday 24 December 2015

Integration by parts



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I have done the 1st part of question and the answer I got is $\frac{5e^4 - 1}{32} $which I verified from the calculator too. But I am confused how to approach to the deducing part using previous result(since it is stated HENCE ). Any help is greatly appreciated.


Answer



Substitute $t=x^2$ and you will get:



$$A = \frac 12 \int_1^e t^3(\ln\sqrt{t})^2 dt = \frac 18 \int_1^e t^3(\ln t)^2dt$$


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