Wednesday, 14 December 2016

algebra precalculus - Solving [(1-λ)a^{-p} +λb^{-p}]^{frac{-1}{p}}=C for the variable b

How can I approach solving [(1-λ)a^{-p} +λb^{-p}]^{\frac{-1}{p}}=C for the variable b



When the given answer is b =λ^{\frac{1}{pc^{p(1-λ)a^{-p^{\frac{-1}{p}}}}}}




Could someone elaborate the reasoning behind steps to reaching the above solution.
Very much appreciated.



Thanks in advance.

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