How do i solve the below without using L'hopital rule. The final answer obtained is 2/3
lim
How do i go about solving using limit of
\lim_{x\to 0}\frac{\sin x}{x}=0,\\ \lim_{x\to 0}\frac{\tan x}{x}=1
I was shown to this step but how do i get to it?
How do i solve the below without using L'hopital rule. The final answer obtained is 2/3
lim
How do i go about solving using limit of
\lim_{x\to 0}\frac{\sin x}{x}=0,\\ \lim_{x\to 0}\frac{\tan x}{x}=1
I was shown to this step but how do i get to it?
How to find \lim_{h\rightarrow 0}\frac{\sin(ha)}{h} without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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