Prove that [0,1]≈[0,a) where a is a positive real number.
I know I need to fine a bijective function function between the two sets. The a in the second set is throwing me off. Origninally I was thinking of doing x=1a that would get me [0,x). But i am unsure if this is the correct route. Also how do I address the open interval on a as oppose to a closed interval?
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