Monday 31 July 2017

calculus - How does $frac{1}{cos y}$ = $frac{1}{sqrt{1-x^2}}$

I was going through a textbook of mine and I noticed that in the proof of derivative of

$y = \sin^{-1}$,



i.e. proof that $$\frac{dy}{dx} \sin^{-1}(x) = \frac{1}{\sqrt{1-x^2}}$$



there's a point where they say $$\frac{1}{\cos y} = \frac{1}{\sqrt{1-x^2}}$$



and I'm not sure how this makes sense or works out. I've looked for proofs, tried implicit differentiation, and tried graphing it, but couldn't find anything. Can someone please explain?

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