Sunday, 16 July 2017

convergence divergence - Average of Random variables converges in probability.




Let $(\Omega, F, P)$ be probability theory.



Suppose that $X_1, X_2, X_3,...$ be sequence of random variable and $E(X_i)=0$ for all $i\in \mathbb{N}$.



Let $Y_n=\frac{X_1+X_2+... +X_n}{n}$.



claim . $Y_n$ converges to 0 in probability.



Let $A_n=\{w : |Y_n(w)| > \epsilon >0\}$




$$\int _{A_n} |Y_n| dP \geq \int_{A_n} \epsilon dP \geq P(A_n) \epsilon$$



But $|Y_n| \leq |X_1|/n + |X_2|/n +... |X_n|/n$ so $P(A_n)=0$.



is it right?


Answer



If you assume the $X_i$ are iid, this is the Weak Law of Large Numbers. Without that assumption (or some slight generalizations of it), the statement is false.


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