Can someone help me with this limit? I'm working on it for hours and cant figure it out.
limx→0(tanxx)1x2
I started transforming to the form
limx→0eln(tanxx)x2
and applied the l'Hopital rule (since indeterminated 00), getting:
limx→0(2x−sin2x2x2sin2x)
From here, I try continue with various forms of trigonometric substitutions, appling the l'Hopital rule again and again, but no luck for me. Can someone help me?
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