$\int_{-\infty}^{\infty}\sin^2(x)/x^2=\pi$ according to wolfram alpha. That is such a beautiful result! But how do I calculate this integral by hand?
Thanks in advance.
Answer
The answer may be found by using complex analysis, specifically the residue theorem. A full deriviation may be found here.
I know of an easy way to derive this result using real analysis alone.
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