Wednesday 30 August 2017

integration - how to calculate the integral of $sin^2(x)/x^2$











$\int_{-\infty}^{\infty}\sin^2(x)/x^2=\pi$ according to wolfram alpha. That is such a beautiful result! But how do I calculate this integral by hand?



Thanks in advance.


Answer



The answer may be found by using complex analysis, specifically the residue theorem. A full deriviation may be found here.



I know of an easy way to derive this result using real analysis alone.


No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...