Thursday, 7 June 2018

calculus - Show that a recursive sequence converges





Let a1=1,a2=2 and an=12(an1+an2)
Show that the sequence converges.




At first I thought using the theorem which says that a bounded and monotone sequence converges, but the sequence (at least the first terms) is not monotone.



I suspect I should use Cauchy's criteria but don't know how to apply it here.



Be glad for help.


Answer




We can prove that |anan1|=12n2



You can check that it works for n=2. Assuming it holds for n, we have |an+1an|=|an+an12an|=12|an1an|=12|anan1|=1212n2=12n+12



This should lead to a proof of convergence.


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