Let a1=1,a2=2 and an=12(an−1+an−2)
Show that the sequence converges.
At first I thought using the theorem which says that a bounded and monotone sequence converges, but the sequence (at least the first terms) is not monotone.
I suspect I should use Cauchy's criteria but don't know how to apply it here.
Be glad for help.
Answer
We can prove that |an−an−1|=12n−2
You can check that it works for n=2. Assuming it holds for n, we have |an+1−an|=|an+an−12−an|=12|an−1−an|=12|an−an−1|=1212n−2=12n+1−2
This should lead to a proof of convergence.
No comments:
Post a Comment