I have this problem that I cannot seem to solve. I tried splitting it into two factors lim but that did not help because of the +1 in the denominator. So I tried multiplying both powers by \frac{2n+1}{2n+1} but that did not help either. So now I'm stuck,and don't know what to do
can someone please help? Thanks
Answer
Hint: write 3n = \dfrac{3}{2}(2n+1) - \dfrac{3}{2}, and use the fact that \displaystyle \lim_{n\to \infty} \left(1-\dfrac{1}{2n+1}\right)^{2n+1} = \dfrac{1}{e}. Can you take it from here?
No comments:
Post a Comment