Problem 4. use the principle of induction to verify:
n∑k=1k2=n(n+1)(2n+1)6
base case is obviously easy, but I don't know how to prove the inductive case
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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