Saturday, 13 July 2019

trigonometry - Proving the identity cscxsinx=(cotx)(cosx)



We recently started Trigonometry and I was trying to solve this.



cscxsinx=(cotx)(cosx)



So starting with LHS:
1sinxsinx=1(sinx)2sinx=(cosx)2sinx



I am stuck now and wanted to know how should I proceed. Is this much correct?


Answer



Its done. Just split the numerator as:



cosx.cosxsinx



=cosxsinx.cosx




=cotx.cosx



Proved!


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