Thursday, 7 November 2019

calculus - Convergence or divergence for infinite series suminftyn=1frac(1)5(5)nn5n



Can someone please explain why this diverges or converges and explain which test they used? For some reason my mind isn't working today and I am getting really frustrated.



n=1((1)5)((5)n)n5n



Answer



Take out 1 negative sign from (5)n, and you will see that the series can be written as n=1(1)nn. This is (conditionally) convergent by alternating series test.


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...